Count of Smaller Numbers After Self

Algorithms
Hard
Tesla
50.8K views

Given an integer array `nums`, return an array `counts` where `counts[i]` is the number of elements to the right of `nums[i]` that are strictly smaller than `nums[i]`. Use a modified Merge Sort or Fenwick Tree/Segment Tree.

Why Interviewers Ask This

Tesla evaluates this question to assess a candidate's ability to optimize brute-force solutions for real-time systems. They specifically look for mastery of divide-and-conquer strategies or advanced data structures like Fenwick Trees, which are critical for handling high-volume sensor data processing efficiently within their autonomous driving stacks.

How to Answer This Question

1. Clarify constraints immediately: Ask about array size and value ranges to determine if O(n^2) is acceptable or if O(n log n) is mandatory. 2. Propose the optimal strategy: Explicitly state you will use Merge Sort or a Binary Indexed Tree (Fenwick Tree) to achieve logarithmic time complexity per element. 3. Explain the logic clearly: For Merge Sort, describe how counting smaller elements happens during the merge phase by comparing left and right subarrays. For Fenwick Trees, explain coordinate compression and updating indices from right to left. 4. Walk through a dry run: Use a small example like [5, 2, 6, 1] to trace the algorithm step-by-step, showing exactly how the count updates. 5. Discuss trade-offs: Briefly mention space complexity versus implementation complexity, demonstrating awareness of memory constraints relevant to Tesla's embedded environments.

Key Points to Cover

  • Explicitly identifying the need for O(n log n) complexity over O(n^2)
  • Explaining the specific mechanism of counting during the merge phase
  • Demonstrating understanding of coordinate compression if using a Fenwick Tree
  • Providing a clear, step-by-step dry run with a concrete example array
  • Acknowledging space complexity implications for embedded systems

Sample Answer

To solve the Count of Smaller Numbers After Self problem efficiently, I would avoid the naive O(n^2) nested loop approach, as it won't scale for large datasets typical in automotive telemetry. Instead, I recommend a modi…

Common Mistakes to Avoid

  • Implementing a brute force O(n^2) solution without discussing optimization due to time constraints
  • Forgetting to handle duplicate values correctly when strictly smaller comparisons are required
  • Confusing the direction of iteration, failing to process elements from right to left for tree-based approaches
  • Skipping the explanation of why standard sorting algorithms alone cannot solve the problem without modification

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