Can you find a triplet such that a squared equals b squared plus c squared?

I would start by sorting the array to facilitate efficient searching. Once sorted, I can iterate through each element to treat it as the potential hypotenuse. For each element, I use two pointers starting from the beginning and end of the remaining subarray to find if there exist two numbers whose squares sum up to the square of the current element. This reduces the problem to O(N^2) time complexity, which is a significant improvement over the naive O(N^3) approach while maintaining reasonable space usage.