Let \triangle A B C be an isosceles triangle such that A B and A C are of equal length. A D is the altitude from A on B C and B E is the altitude from \mathrm{B} on \mathrm{AC}. If \mathrm{AD} and \mathrm{BE} intersect at \mathrm{O} such that \angle \mathrm{AOB}=105^{\circ}, then \frac{A D}{B E} equals

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CAT 2023 Slot 3 QA · Question 17

Let $△ A B C$ be an isosceles triangle such that $A B$ and $A C$ are of equal length. $A D$ is the altitude from $A$ on $B C$ and $B E$ is the altitude from $B$ on $AC$ . If $AD$ and $BE$ intersect at $O$ such that $∠ AOB = 10 5^{\circ}$ , then $\frac{A D}{B E}$ equals

A.
$2 sin 1 5^{\circ}$
B.
$cos 1 5^{\circ}$
C.
$2 cos 1 5^{\circ}$
D.
$sin 1 5^{\circ}$

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