If x 0 = 1, x 1 = 2, and x n + 2 = \frac{1+x_{n+1}}{x_{n}}, n = 0, 1, 2, 3,..., then x 2021 is equal to?

CAT 2021 Slot 1 QA · Question 22

If x₀ = 1, x₁ = 2, and x_{n + 2} = $\frac{1 + x _{n + 1}}{x _{n}}$ , n = 0, 1, 2, 3,..., then x₂₀₂₁ is equal to?